Problems involving centripetal force and acceleration

Problems involving centripetal acceleration often ask for the speed or radius at which the centripetal acceleration meets a specified value. For example, the safe radius for a curve on a roadway depends on the speed of the cars on that road. High-speed roads require large-radius curves. The redline for a car engine is related to the centripetal acceleration applied to the piston by the rotating crankshaft. If the engine spins too fast the force required to accelerate the piston breaks the connecting rod in a spectacular (and expensive) engine malfunction. Read the text aloud
What is the minimum radius of the curve for a car traveling 30 m/s? The Federal Highway Association guidelines suggest a maximum safe sideways acceleration in a turn of 0.1g, or 1 m/s2. What is the minimum radius at which a civil engineer should design a curve on a road intended for cars traveling at up to 30 m/s (67 mph)? Read the text aloud
Asked: radius R
Given: v = 30 m/s, ac = 1 m/s2
Relationships: ac = v2/R
Solution: Solve the equation for the radius:
ac = v2/RR = v2/ac
R = (30 m/s)2 ÷ (1 m/s2) = 900 m
The minimum radius is 900 m (about 3,000 ft).
Show Why are highway curves sharper than this?
What is the maximum safe operating speed of the engine? A high-performance car engine has a piston and connecting rod that have a combined reciprocating mass of 500 g. The connecting rod can safely sustain a force of 20,000 N. The radius of the crankshaft is 5.0 cm (0.050 m). What is the maximum safe operating speed of the engine in revolutions per minute? Read the text aloud
Asked: rotational speed ω in rpm
Given: m = 0.500 kg, F = 20,000 N, R = 0.050 m
Relationships: Fc = mv2/R, v = ωR, 1 rad/s = 9.55 rpm
Solution: First, put the force equation in terms of angular speed ω: F c = m v 2 R F c = m (ωR) 2 R =m ω 2 R Next, calculate ω: ω= F c mR = 20,000 N (0.500 kg)(0.050 m) = 894 rad/s 894 rad/s ( 9.55 rpm 1 rad/s )=8,500 rpm
Answer: 8,500 rpm

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